7(5p^2+26p-168)=0

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Solution for 7(5p^2+26p-168)=0 equation:



7(5p^2+26p-168)=0
We multiply parentheses
35p^2+182p-1176=0
a = 35; b = 182; c = -1176;
Δ = b2-4ac
Δ = 1822-4·35·(-1176)
Δ = 197764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{197764}=\sqrt{196*1009}=\sqrt{196}*\sqrt{1009}=14\sqrt{1009}$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(182)-14\sqrt{1009}}{2*35}=\frac{-182-14\sqrt{1009}}{70} $
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(182)+14\sqrt{1009}}{2*35}=\frac{-182+14\sqrt{1009}}{70} $

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